题解 | #获得积分最多的人(一)#
获得积分最多的人(一)
http://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
/*
SELECT u.name, sum(info.grade_num) as grade_sum
from user as u
right JOIN grade_info as info
ON u.id = info.user_id
GROUP BY info.user_id
*/
SELECT t.name, t.grade_sum
FROM (SELECT u.name as name, sum(info.grade_num) as grade_sum
from user as u
right JOIN grade_info as info
ON u.id = info.user_id
GROUP BY info.user_id) as t
ORDER BY grade_sum DESC
limit 1;
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