题解 | #提取不重复的整数#

C++

#include<iostream>
#include<map>
using namespace std;
int main()
{
    int num;
    cin>>num;
    map<int,int> repeat;
    while(num)
    {
        int temp = num%10;
        if(repeat.find(temp)== repeat.end()) 
        {
            repeat[temp] = 0;
            cout<<temp;
        }
        num = num/10;
    }
}