题解 | #句子逆序#python

python 解法简单易懂

n = list(input().split(";"))
n.pop()
v = [0,0]
for i in n :
    if i[0:1].isalpha() == True:
        if i[1:].isdigit() == True :
            if i[0] == "A":
                nn = i[1:]
                nn = int(nn)
                v[0] = int(v[0]) - nn 
            if i[0] == "D":
                nn = int(i[1:])
                v[0] = int(v[0]) + nn 
            if i[0] == "W":
                nn = int(i[1:])
                v[1] = int(v[1]) + nn 
            if i[0] == "S":
                nn = int(i[1:])
                v[1] = int(v[1]) - nn 
        else:
            continue
    else:
        continue
print(",".join(str(i) for i in v))