Java-LeetCode1356. 根据数字二进制下 1 的数目排序-Comparator
- 算法
- Java-Integer, Comparator
public int[] sortByBits(int[] arr) {
Integer[] integers = new Integer[arr.length];
for (int i = 0; i < arr.length; i++) {
integers[i] = arr[i];
}
// Arrays.sort(integers, (o1, o2) -> Integer.bitCount(o1) == Integer.bitCount(o2) ? o1 - o2 : Integer.bitCount(o1) - Integer.bitCount(o2));
Arrays.sort(integers, Comparator.comparing(x -> Integer.bitCount(x) * 10000 + x));
for (int i = 0; i < arr.length; i++) {
arr[i] = integers[i];
}
return arr;
} LeetCode题解 文章被收录于专栏
测试
