这种题真的没意思...

不是说简单，是说学不到啥新知识，全靠debug，真的烦。

#include <bits/stdc++.h>

using namespace std;

int main()
{

    string alb("ABCDEFGHIJKLMNOPQRSTUVWXYZ");
    string key;
    string odata;
    string albtxt;
    while (getline(cin,key)) {
        getline(cin, odata);
        albtxt = alb;
        // 处理key
        bool appeard[26];
        memset(appeard, 0, sizeof(appeard));
        string pkey = key;

        // key先去重
        for (int i = 0; i<pkey.length();) {
            // 先转成大写字母
            pkey[i] = (pkey[i] >= 'a'&&pkey[i] <= 'z') ? pkey[i] - 'a' + 'A' : pkey[i];
            if (pkey[i] <= 'Z'&&pkey[i] >= 'A') {
                if (appeard[pkey[i] - 'A']) {
                    // 如果出现过该字母，删除该字母
                    pkey.erase(i,1);
                }
                else {
                    appeard[pkey[i] - 'A'] = true;
                    i++;
                }
            }
        }
        // 处理字母表
        string temp;
        for (int i = 0; i<pkey.size();i++) {
            if (pkey[i] <= 'Z'&&pkey[i] >= 'A') {
                albtxt[pkey[i] - 'A'] = 127;
            }
        }
        sort(albtxt.begin(), albtxt.end());
        albtxt = albtxt.substr(0,unique(albtxt.begin(), albtxt.end())-albtxt.begin()-1);

        albtxt = pkey + albtxt;    // 密码表

                                   // 加密
        for (int i = 0; i<odata.size(); i++) {
            if (odata[i] >= 'A'&&odata[i] <= 'Z') {
                odata[i] = albtxt[odata[i] - 'A'];
            }
            else if (odata[i] >= 'a'&&odata[i] <= 'z') {
                odata[i] = albtxt[odata[i] - 'a'] - 'A' + 'a';
            }
        }

        // 输出
        cout << odata << endl;
        odata.clear();
        albtxt.clear();
        key.clear();
    }



}