java采用取余方式拿到后面的数
数字颠倒
http://www.nowcoder.com/questionTerminal/ae809795fca34687a48b172186e3dafe
a%10取个位然后输出,a/=10去掉个位,循环直到输出所有数字。
import java.util.Scanner;
public class Main{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
while(sc.hasNext()){
int n = sc.nextInt();
if(n == 0){
System.out.println(0);
}
int yu = 0;
while(n != 0){
yu = n % 10;
n = n / 10;
System.out.print(yu);
}
}
}}
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