井字棋（Python实现）

这里我们需要用矩阵中的关键值进行比较，这里取矩阵正对角线上的三个值，比较方式如图：
关键值为A[1][1]

关键值为A[0][0]

关键值为A[2][2]

具体代码如下：

Qipan = [list(input().strip().split()) for i in range(3)]
Caipan1,Caipan2,Caipan3 = False,False,False
if Qipan[1][1] != 'O' :
    if (Qipan[0][0] == Qipan[1][1] == Qipan[2][2]) or (Qipan[0][2] == Qipan[1][1] == Qipan[2][0]) :
        Caipan1 = True
    elif (Qipan[0][1] == Qipan[1][1] == Qipan[2][1]) or (Qipan[1][0] == Qipan[1][1] == Qipan[1][2]) :
        Caipan1 = True
    if Caipan1 :
        if Qipan[1][1] == 'K' :
            print('KiKi wins!')
        if Qipan[1][1] == 'B' :
            print('BoBo wins!')
if Qipan[0][0] != 'O' :
    if (Qipan[1][0] == Qipan[0][0] == Qipan[2][0]) or (Qipan[0][1] == Qipan[0][0] == Qipan[0][2]) :
        Caipan2 = True
    if Caipan2 :
        if Qipan[0][0] == 'K' :
            print('KiKi wins!')
        if Qipan[0][0] == 'B' :
            print('BoBo wins!')
if Qipan[2][2] != 'O' :
    if (Qipan[2][0] == Qipan[2][2] == Qipan[2][1]) or (Qipan[0][2] == Qipan[2][2] == Qipan[1][2]) :
        Caipan3 = True
    if Caipan3 :
        if Qipan[2][2] == 'K' :
            print('KiKi wins!')
        if Qipan[2][2] == 'B' :
            print('BoBo wins!')
if Caipan1 == Caipan2 == Caipan3 == False :
    print('No winner!')