py3

思路：x+y = tsum ，那么y = tsum -x ，只需要遍历array，for x in array，判断tsum-x 是否in array即可。有的话加入列表中。array遍历结束后，用内置的sort进行排序即可

# -*- coding:utf-8 -*-
class Solution:
    def FindNumbersWithSum(self, array, tsum):
        # write code here
        if not array or not tsum:
            return []
        result = []
        for i in array:
            if (tsum - i) in array:
                result.append([i, tsum - i])
        if result:
            result.sort(key=lambda x: x[0] * x[1])
            result = result[0]
            result.sort()
            return result
        return []