python实现leetcode-第7题-整数反转

import math
class Solution:
    def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        strX = str(x)
        
        if strX[0] != '-':
            strX1 = strX[::-1]
            x = int(strX1) 
            if x >-2147483648 and x <2147483647:
                x = x
            else:
                x = 0
        else:
            strX1 = strX[1:][::-1]
            x = -1*int(strX1)
            if x >-2147483648 and x <2147483647:
                x = x
            else:
                x = 0
        return x

注意：

1 python自带的字符串操作

2 注意判断溢出，判断正负号

3 python中的与操作是and而不是&