python学习日记3

在周末休息下降1%时，工作日努力多少，能够达到365天，天天努力1%的效果
#DayDayUpQ4.py
def dayUP(df):
      dayup=1
      for i in range(365):
           if i % 7 in [6,0]:
              dayup=dayup*(1-0.01)
           else:
               dayup=dayup*(1+df)
      return dayup
dayfactor=0.01
while dayUP(dayfactor)<37.78:
          dayfactor+=0.001
print('工作日努力的参数:{:.3f}'.format(dayfactor))