请问下,如果统计薪资涨幅(为正)超过15次,以下代码可以吗? (因为楼主补充的代码牛客总是报错) select emp_no,count(*) t from (select *, salary-(LAG(salary,1) over(partition by emp_no order by to_date)) as 工资涨幅 from salaries ) as s2 where s2.工资涨幅>0 group by s2.emp_no having t>=15
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