题解 | 斗兽棋

import sys

# for line in sys.stdin:
#     a = line.split()
#     print(int(a[0]) + int(a[1]))


# s = input().split()

# def trans(x):
#     num = 0
#     if x == 'elephant':
#         num = 4
#     if x == 'tiger':
#         num = 3
#     if x == 'cat':
#         num = 2
#     if x == 'mouse':
#         num = 1
#     return num

# s = [trans(x) for x in s]

# if s[0] == 4 and s[1] ==1 :
#     print('lose')
# elif s[0] == 1 and s[1] ==4:
#     print('win')
# elif s[0] == s[1]+1:
#     print('win')
# elif s[0]==s[1]-1:
#     print('lose')
# else:
#     print('tie')

# 这是个字典类型的
rules = {"elephant": "tiger", "tiger": "cat", "cat": "mouse", "mouse": "elephant"}

s1, s2 = map(str, input().strip().split())

if rules[s1] == s2:    #字典类型，如果s1是elephant则返回的是tiger
    print("win")
elif rules[s2] == s1:
    print("lose")
else:
    print("tie")

唯一需要注意的就是 必须两者相邻，才会有输赢，越级是平手