题解 | 牛牛的线段
牛牛的线段
https://www.nowcoder.com/practice/f72c56ed71664af082c921bf79861c85
#include <stdio.h>
int main() {
int a=0,b=0;
int c=0,d=0;
scanf("%d %d",&a,&b);
scanf("%d %d",&c,&d);
printf("%d",(a-c)*(a-c)+(b-d)*(b-d));
return 0;
}