题解 | 二进制不同位数
二进制不同位数
https://www.nowcoder.com/practice/daf9032926614dab91ca624a7759a868
#include <stdio.h>
int count1bits(int x) {
int count = 0;
for (int i = 0; i < 32; ++i) {
if (x & (1 << i)) {
++count;
}
}
return count;
}
int main() {
int m, n;
scanf("%d %d", &m, &n);
printf("%d\n", count1bits(m ^ n));
return 0;
}
