题解 | 顺时针旋转矩阵
顺时针旋转矩阵
https://www.nowcoder.com/practice/2e95333fbdd4451395066957e24909cc
import java.util.*;
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param mat int整型二维数组
* @param n int整型
* @return int整型二维数组
*/
public int[][] rotateMatrix (int[][] mat, int n) {
//先上下翻转
for (int i = 0; i < n / 2; i++) {
for (int j = 0; j < n; j++) {
int tmp = mat[i][j];
mat[i][j] = mat[n - i - 1][j];
mat[n - i - 1][j] = tmp;
}
}
//再按对角线翻转
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
int tmp = mat[i][j];
mat[i][j] = mat[j][i];
mat[j][i] = tmp;
}
}
return mat;
}
}
