题解 | 访问单个节点的删除
访问单个节点的删除
https://www.nowcoder.com/practice/6a668a3960e24d3ea04bba89109c6451
# -*- coding:utf-8 -*-
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Remove:
def removeNode(self, pNode):
# write code here
if pNode.next == None:
return False
else:
pNode.val = pNode.next.val
pNode.next = pNode.next.next
return True