题解 | 凯撒加密
凯撒加密
https://www.nowcoder.com/practice/006b7917d3784371a43cfbae01a9313d
#include <iostream>
using namespace std;
#include <string>
char letter[] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t',
'u','v','w','x','y','z'};
int main() {
int n;
cin >> n;
string s;
cin >> s;
for(int i=0;i<s.length();i++)
{
s[i] = letter[(s[i]-'a'+n)%26];
}
cout << s;
}
// 64 位输出请用 printf("%lld")