题解 | 公共子串计算

import sys

lines = sys.stdin.readlines()
s1 = lines[0].strip()
s2 = lines[1].strip()
if len(s1) > len(s2):
    s1,s2 = s2,s1

length = 1


for length in range(1,len(s1)+1):
    has_son_str = False # 每次取新length时需要重置为False
    for i in range(len(s1)-length+1):
        char = s1[i:i + length]
        if char in s2: # 存在公共子串，打破当前对s1的循环，进入对length的循环
            has_son_str = True
            break   
    if not has_son_str: # 当length取某值时，对s1遍历无子串，则无超过length-1长度的字段
        length = length -1
        break

print(length)

出错时先找变量名是否有写错