题解 | 括号配对问题

s = list(input())
you = []
stack = []
for x in s:
    if x=='(' or x==')'or x=='['or x==']':
        you.append(x)
if len(you)%2==0 and you[0] != ']'and you[0]!=')':
    for x in you:
        if x == '(' or x == '[':
            stack.append(x)
        elif (x == ')' and stack[len(stack)-1] == '(') or  (x == ']' and stack[len(stack)-1] == '['):
            stack.pop()
        else:
            break
    if len(stack)==0:
        print("true")
    else:
        print("false")
else:
    print("false")
        

遍历取数浪费了时间，但可以len(you)%2==0 and you[0] != ']'and you[0]!=')'可以节约判断遍历时间