题解 | 田忌赛马
田忌赛马
https://www.nowcoder.com/practice/49d799f65a0749588e9cd7e6135a4a9a
#include <stdio.h>
int max(int a,int b,int c){
int mm=a;
if(mm<b) mm=b;
if(mm<c) mm=c;
return mm;
}
int min(int a,int b,int c){
int mm=a;
if(mm>b) mm=b;
if(mm>c) mm=c;
return mm;
}int mon(int a,int b,int c){
int mm;
if(a <= max(a,b,c) && a>min(a,b,c) ) mm=a;
if(b <= max(a,b,c) && b>min(a,b,c) ) mm=b;
if(c <= max(a,b,c) && c>min(a,b,c) ) mm=c;
return mm;
}
int main() {
int v[6],t,num=0;
for (int i=0; i<6; i++) {
scanf("%d",&v[i]);
}
if(max(v[3],v[4],v[5])>mon(v[0],v[1],v[2]) && mon(v[3],v[4],v[5])>min(v[0],v[1],v[2]))
printf("Yes");
else printf("No");
return 0;
}