题解 | 田忌赛马
田忌赛马
https://www.nowcoder.com/practice/49d799f65a0749588e9cd7e6135a4a9a
qi = list(map(int,input().split()))
tian = list(map(int,input().split()))
qi.sort(reverse=True)
tian.sort(reverse=True)
#排序后，田最快的马和第二快的马比齐第二快的马和最慢的马快就赢
flag = (tian[0] > qi[1]) and (tian[1] > qi[2])
if flag:
print("Yes")
else:
print("No")
