题解 | 旺仔哥哥挤地铁
旺仔哥哥挤地铁
https://www.nowcoder.com/practice/1e683db4a34442098fb642d514bd0794
import sys
import re
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 计算旺仔哥哥在地铁上的最长停留时间
# @param t int整型一维数组 序列 t,表示地铁在相邻两站之间的用时
# @param s int整型一维数组 序列 s,表示地铁在每一站的停靠时间
# @param x int整型 旺仔哥哥想从第 x 站出发
# @param y int整型 旺仔哥哥想坐到第 y 站
# @return int整型
#
class Solution:
def countLongestSubwayTime(self, t: list[int], s: list[int], x: int, y: int) -> int:
# write code here
s_time = 0
t_time = 0
for i in range(x - 1, y):
s_time = int(s[i]) + s_time
for i in range(x - 1, y - 1):
t_time = int(t[i]) + t_time
return s_time + t_time
if __name__ == "__main__":
t = []
s = []
for line in sys.stdin:
a = line.split()
# print(a)
lst = re.findall(r"\d+", a[0])
# print(lst)
for i in range(int((len(lst) - 3) / 2)):
t.append(lst[i])
for i in range(
int((len(lst) - 3) / 2), int((len(lst) - 3) / 2) + int((len(lst) - 1) / 2)
):
s.append(lst[i])
x = int(lst[len(lst) - 2])
y = int(lst[len(lst) - 1])
res = Solution().countLongestSubwayTime(t, s, x, y)
print(res)