题解 | 【模板】序列操作
【模板】序列操作
https://www.nowcoder.com/practice/12da4185c0bb45918cfdc3072e544069
import sys
def solve():
input = sys.stdin.read
data = input().split() # 数据读取
# print(data) ['5', '1', '8', '1', '9', '7', '1', '6', '8']
n = int(data[0])
seq = []
index = 1
output_lines = []
for _ in range(n):
op = data[index]; index += 1
if op == '1':
x = int(data[index]); index += 1
seq.append(x)
elif op == '2':
# if seq:
seq.pop()
elif op == '3':
i = int(data[index]); index += 1
# print(seq[i])
output_lines.append(str(seq[i]))
elif op == '4':
i = int(data[index]); index += 1
x = int(data[index]); index += 1
seq.insert(i+1, x) # 在 下标 i和i+1间插入x
elif op == '5':
seq.sort() # 从小到大排序
elif op == '6':
seq.sort(reverse=True)
elif op == '7':
# print(len(seq))
output_lines.append(str(len(seq)))
elif op == '8':
# print(' '.join(map(str,seq)))
# ' '.join 拼接字符串
# map(函数, 可迭代对象)
output_lines.append(' '.join(map(str, seq)))
# 输出所有结果
print('\n'.join(output_lines))
solve()
结果收集后再输出 26ms
结果实时输出 88ms
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