题解 | 比较版本号

# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 比较版本号
# @param version1 string字符串 
# @param version2 string字符串 
# @return int整型
#
class Solution:
    def compare(self , version1: str, version2: str) -> int:

        # 点分割，整数化
        version1_l = version1.split('.')
        version2_l = version2.split('.')
        version1_l = [int(i) for i in version1_l]
        version2_l = [int(i) for i in version2_l]
        
        # 补齐0
        if len(version1_l)!=len(version2_l):
            max_len = max(len(version1_l),len(version2_l))
            min_l = version1_l if len(version1_l)<len(version2_l) else version2_l
            for i in range(max_len-len(min_l)):
                min_l.append(0)
        
        # 比较
        version1_l = tuple(version1_l)
        version2_l = tuple(version2_l)
        if version1_l<version2_l:
            return -1
        elif version1_l>version2_l:
            return 1
        else:
            return 0