题解 | 特殊的科学计数法
特殊的科学计数法
https://www.nowcoder.com/practice/ca0962879d3b40d8bb598fb9a905ac7a
n = str(input())
if int(n[2]) >= 5:
if int(n[1]) == 9:
if int(n[0]) == 9:
a = 1
b = 0
c = len(n)
else:
a = int(n[0])+1
b = 0
c = len(n) - 1
else:
a = int(n[0])
b = int(n[1]) + 1
c = len(n) - 1
else:
b = int(n[1])
a = int(n[0])
c = len(n) - 1
print(f'{a}.{b}*10^{c}')


