题解 | A + B

#include <bits/stdc++.h>
using namespace std;
int Cheng(string s) {
    int a;
    if (s == "one") {
        a = 1;
    } else if (s == "two") {
        a = 2;
    } else if (s == "three") {
        a = 3;
    } else if (s == "four") {
        a = 4;
    } else if (s == "five") {
        a = 5;
    } else if (s == "six") {
        a = 6;
    } else if (s == "seven") {
        a = 7;
    } else if (s == "eight") {
        a = 8;
    } else if (s == "nine") {
        a = 9;
    } else {
        a = 0;
    }
    return a;
}

int main() {
    string s;
    while (getline(cin, s)) { // 注意 while 处理多个 case
        vector<string> x;
        string s1, s2;
        int l = 0;
        for (int i = 0; i < s.size(); i++) {
            if (s[i] == '=') {
                break;
            } else if (s[i] == '+') {
                l = i;
            } else if (s[i] == ' ') {
                x.push_back(s.substr(l, i - l));
                l = i + 1;
            }
        }
        int i, a = 0, b = 0;
        for (i = 0; i < x.size(); i++) {
            if (x[i] == "+") {
                break;
            }
            a = a * 10 + Cheng(x[i]);
        }
        // cout << a << " " << b << endl;
        for (i = i + 1; i < x.size(); i++) {
            b = b * 10 + Cheng(x[i]);
        }
        if (a == 0 && b == 0) {
            break;
        }
        cout << a + b << endl;
    }
}