题解 | 跳台阶扩展问题
跳台阶扩展问题
https://www.nowcoder.com/practice/22243d016f6b47f2a6928b4313c85387
class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param number int整型 * @return int整型 */ int jumpFloorII(int number) { // write code here vector<int> dp(number + 1,0); dp[0] = 0; dp[1] = 1; dp[2] = 2; vector<int> presum(number + 1, 0); presum[0] = 0; presum[1] = 1; for(int i = 3; i < number + 1; i ++){ presum[i - 1] = presum[i - 2 ] + dp[i - 1]; dp[i] = presum[i - 1] + 1; } return dp[number]; } };