题解 | 删除字符串中出现次数最少的字符

str_list = list(input().strip())

# 将每个字母出现的次数做成一个字典
letter_dict = {}
for letter in str_list:
    if letter not in letter_dict.keys():
        letter_dict[letter] = 1
    else:
        letter_dict[letter] += 1
# 找出最小出现的次数
min_num = letter_dict[str_list[0]]
for letter,num in letter_dict.items():
    if num <= min_num:
        min_num = num
#  遍历原来的列表，跳过最小出现次数列表对应的字母
result = [char for char in str_list if letter_dict[char] != min_num]
print(''.join(result))