题解 | 牛牛的并联电路
牛牛的并联电路
https://www.nowcoder.com/practice/6e13936b6fc54f52ac22efd6c8e7fef3
#include <stdio.h>
int main()
{
int r1 = 0;
int r2 = 0;
scanf("%d %d", &r1, &r2);
printf("%.1f\n", 1.0 / ((1.0 / r1) + (1.0 / r2)));
return 0;
}
牛牛的并联电路
https://www.nowcoder.com/practice/6e13936b6fc54f52ac22efd6c8e7fef3
#include <stdio.h>
int main()
{
int r1 = 0;
int r2 = 0;
scanf("%d %d", &r1, &r2);
printf("%.1f\n", 1.0 / ((1.0 / r1) + (1.0 / r2)));
return 0;
}
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