题解 | 链表内指定区间反转
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
import java.util.*;
/*
* public class ListNode {
* int val;
* ListNode next = null;
* public ListNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @param m int整型
* @param n int整型
* @return ListNode类
*/
public ListNode reverseBetween (ListNode head, int m, int n) {
ListNode tempreNode = new ListNode(0);
tempreNode.next = head;
ListNode head1 = tempreNode;
ListNode index = tempreNode;
ListNode mHead = tempreNode;
ListNode mHead1Index = tempreNode;
ListNode nTail = tempreNode;
ListNode mPre = tempreNode;
if(m == 1&&n == 1){
return head;
}
for(int i = 0;i<=n ;i++){
if(i == m){
mHead = head1;
index = head1;
mHead1Index = head1;
}
if(i == n){
nTail = head1;
}
if(i == m-1){
mPre = head1;
}
head1 = head1.next;
}
ListNode tail = nTail.next;
mPre.next = null;
nTail.next = null;
while(index!=nTail){
index = index.next;
mHead.next = null;
if(nTail.next == null){
nTail.next = mHead;
}else{
mHead.next = nTail.next;
nTail.next = mHead;
}
mHead = index;
}
mHead1Index.next = tail;
mPre.next = index;
return tempreNode.next;
// write code here
}
}
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