题解 | xxx定律 --有scanf("%d",&a)!=EOF
xxx定律
https://www.nowcoder.com/practice/75c189249d6145cfa33cd53edae6afc8
#include "stdio.h" using namespace std; int main() { int n = 0; while (scanf("%d", &n) != EOF) { int count = 0; while (n!=1){ count += 1; if (n % 2 == 0) { n = n / 2; } else { n = n * 3 + 1; n = n / 2; } } printf("%d\n", count); } return 0; }