题解 | 杨辉三角
杨辉三角
https://www.nowcoder.com/practice/e671c6a913d448318a49be87850adbcc?tpId=290&tqId=39928&ru=/exam/oj
import java.util.Scanner; //线性dp public class Main{ public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); int[][] dp = new int[n + 1][n + 1]; dp[1][1] = 1; for(int i = 2; i <= n; i++){ for(int j = 1; j <= i; j++){ //线性dp方程 dp[i][j] = dp[i - 1][j] + dp[i - 1][j - 1]; } } for(int i = 1; i <= n; i++){ for(int j = 1; j <= i; j++){ StringBuffer ret = new StringBuffer(); int len = Integer.toString(dp[i][j]).length();//求出该位置字符长度 for(int k = 0; k < 5 - len; k++){//位域宽为5,缺多少位补多少个空格 ret.append(" "); } System.out.print(ret.toString() + dp[i][j]); }//换行 System.out.println(); } } }