题解 | Day of Week

#include <iostream>
using namespace std;
//隐藏条件1年1月1号是周一
int main() {
    int x, y;
    string str;
    cin >> x >> str >> y;
    string s[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
    int f[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    string ss[7] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
    int z = 0;
    for (int i = 0; i < 12; i++) {
        if (str == s[i]) {
            z = i;
            break;
        }
    }
    int sum = 0;
    if (y % 400 == 0 || (y % 4 == 0 && y % 100 != 0))f[1] = 29;
    for (int i = 0; i < z; i++) {
        sum += f[i];
    }
    sum += x;
    for (int i = 1; i < y; i++) {
        if (i % 400 == 0 || (i % 4 == 0 && i % 100 != 0)) sum += 366;
        else sum += 365;
    }
    int h = sum % 7;
    cout << ss[h];
}
// 64 位输出请用 printf("%lld")