题解 | 日期累加

#include <iostream>
using namespace std;

int main() {
    int m;
    cin >> m;
    string s[m];
    for (int z = 0; z < m; z++) {
        int a, b, c = 0, x = 0;
        cin >> a >> b >> c >> x;
        int f[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
        if (a % 400 == 0)f[1] = 29;
        else if (a % 4 == 0 && a % 100 != 0)f[1] = 29;
        else f[1] = 28;
        int sum = 0;
        for (int i = 0; i < b - 1; i++) {
            sum += f[i];
        }
        sum += c + x;
        int d = 0, y = 0; //d表示月份，y表示日期
        for (int i = 0; sum > 0; i++) {
            y = sum;
            sum -= f[i];
            d++;
            if(i==11) i = -1;
            if (d > 12) {
                d -= 12;
                a++;
                if(a%400==0 || (a%4==0 && a%100!=0)) f[1] = 29;
			    else f[1] = 28;
		
            }
        }

        if (d >= 10 && y >= 10)cout << a << "-" << d << "-" << y<<endl;
        else if (d >= 10 && y < 10)cout << a << "-" << d << "-0" << y<<endl;
        else if (d < 10 && y >= 10)cout << a << "-0" << d << "-" << y<<endl;
        else cout << a << "-0" << d << "-0" << y<<endl;

    }

}
// 64 位输出请用 printf("%lld")