题解 | 求int型正整数在内存中存储时1的个数

#include <stdio.h>

int main() {
    int n,res;
    int count = 0;
    scanf("%d",&n);
    while(n != 0){
        res = n % 2;
        if(res == 1){
            count ++;
        }
        n = n / 2;
    }
    printf("%d",count);
    return 0;
}