题解 | 图片整理

def sort_by_ascii(s):
    # 使用字典存储每个字符出现的次数
    char_count = {}
    for char in s:
        if char in char_count:
            char_count[char] += 1
        else:
            char_count[char] = 1
    
    # 按照ASCII码值排序，并构建结果字符串
    sorted_s = ''
    for ascii in range(0, 256):  # ASCII码值范围是0-255
        char = chr(ascii)
        if char in char_count and char_count[char] > 0:
            sorted_s += char * char_count[char]
    
    return sorted_s

# 示例输入
s = input().strip()
# 输出排序后的答案
print(sort_by_ascii(s))