题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
# class ListNode: # def __init__(self, x): # self.val = x # self.next = None # # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param head ListNode类 # @return ListNode类 # class ListNode: def __init__(self,x,next=None): self.val=x self.next=None class Solution: def ReverseList(self , head: ListNode) -> ListNode: # write code here if not head: return None pre=None head1=head while head1: temp=head1.next head1.next=pre pre=head1 head1=temp return pre