题解 | #计算日期到天数转换#__huawei_no.73

#include <iostream>
using namespace std;

int main() {
    int year, month, day;
    int data[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    while (cin >> year >> month >> day) {
        int sum;
        for (int i = 0; i < month - 1; i++) {
            sum = sum + data[i];
        }
        if ((year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) && month > 2)
            sum = sum + 1 + day;
        else
            sum = sum + day;

            cout<<sum<<endl;
    }
    return 0;
}
// 64 位输出请用 printf("%lld")

主要是想到构建一个数组，基本上就能解决问题。