题解 | #单组_spj判断数组之和#
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
nu = input().split(' ')
n = eval(nu[0])
m = eval(nu[1])
list1 = []
if n <= m:
for i in range(n):
if i == n - 1:
list1.append(int(m-i))
break
list1.append(int(1))
last = ' '.join(map(str,list1))
print(last)
