题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* ListNode(int x) : val(x), next(nullptr) {}
* };
*/
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @param m int整型
* @param n int整型
* @return ListNode类
*/
ListNode* reverseBetween(ListNode* head, int m, int n) {
// write code here
ListNode* empty_node = new ListNode(-1);
empty_node->next = head;
//取翻转起始节点前一个
ListNode* pre = empty_node;
for(int i = 0;i < m - 1;i++)
{
pre = pre->next;
}
ListNode *beginNode = pre->next;
// 取翻转终止节点后一个
ListNode *endNode = pre;
for(int i = 0;i < n - m + 1; i++)
{
endNode = endNode->next;
}
ListNode* succ = endNode->next;
endNode->next = nullptr;
reverseList(beginNode);
pre->next = endNode;
beginNode->next = succ;
return empty_node->next;
}
ListNode* reverseList(ListNode* head)
{
ListNode* cur = head;
ListNode* pre = nullptr;
while (cur) {
ListNode* next = cur->next;
cur->next = pre;
pre = cur;
cur = next;
}
return pre;
}
};
查看24道真题和解析