题解 | #牛牛的水杯#

#include <stdio.h>

int main() {
	double h = 0;
	double r = 0;
	double pi = 3.14;
	scanf("%lf %lf", &h, &r);
	double v = pi * r * r * h;
    //求出一杯水的容积
	int i = 0;
	while (v * i <= 10000) {
		i++;
	}
    //求出需要的杯数
	printf("%d", i);
	return 0;
}