题解 | #百钱买百鸡问题#

#include <iostream>
using namespace std;

int main() {
    int n;
    while (cin >> n) { // 注意 while 处理多个 case
        int a = 0, b = 0, c= 0;
        for(int i = 0; i < 21; ++i){
            for(int j = 0; j < 34; j++){
                for(int k = 0; k < 301; k+=3){
                    if(i*5 + j*3 + k/3 == 100 && i+j+k == 100){
                        cout << i << " " << j << " " << k << endl;
                    }
                }
            }
        }
    }
}
// 64 位输出请用 printf("%lld")