题解 | #打印等腰三角形#

#!/bin/bash

read -p "input: " n

for((i=1;i<=n;i++))
do
    for((j=1;j<=n-i;j++))
    do
        echo -n " "
    done
    #打印 i 个 *
    for((k=1;k<=i;k++))
    do
        echo -n "* "
    done
    echo ""
done