题解 | #等差数列#
等差数列
https://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
a=int(input())
def digui(n):
if n==1:
return 2
else:
return 3+digui(n-1)
s=0
for i in range(1,a+1):
s+=digui(i)
print(s)
等差数列
https://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
a=int(input())
def digui(n):
if n==1:
return 2
else:
return 3+digui(n-1)
s=0
for i in range(1,a+1):
s+=digui(i)
print(s)
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