题解 | #计算日期到天数转换#

#include <stdio.h>

int main() {
    int date[3]={0};
    scanf("%d %d %d",&date[0],&date[1],&date[2]);
    int month[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    if(date[0]%4==0)
    {
        if(date[0]%100==0)
        {
            if(date[0]%400==0)
            {
                month[2]=29;
            }
        }
        else {
        month[2]=29;
        }
    }
    int result=0;
    for(int i=0;i<date[1];i++)
    {
        result=month[i]+result;
    }
    result=result+date[2];
    printf("%d\n",result);
    return 0;
}