题解 | #统计字符#

#include <iostream>
#include <string>
using namespace std;

int main() {
    string inp;
    getline(cin, inp);
    int N = inp.size();
    int numC = 0;
    int space = 0;
    int number = 0;
    int other = 0;
    for (int i = 0; i < N; i++) {
        if ((inp[i] >= 'A' && inp[i] <= 'Z') || (inp[i] >= 'a' && inp[i] <= 'z')) {
            numC++;
        } else if (inp[i] == ' ') {
            space++;
        } else if (inp[i] >= '0' && inp[i] <= '9') {
            number++;
        } else other++;
    }
    cout << numC << endl << space << endl << number << endl << other;
}
// 64 位输出请用 printf("%lld")

没什么好说的