立志重刷代码随想录60天冲冲冲!!——第二十三天
39. 组合总和
class Solution {
public:
vector<vector<int>> res;
vector<int> path;
int sum = 0;
void backtracking(vector<int> candidates, int target, int startIdx) {
if (sum == target) {
res.push_back(path);
return;
} else if (sum > target) { // sum大于target也需要返回!!!
return;
}
for (int i = startIdx; i < candidates.size(); i++) {
int num = candidates[i];
path.push_back(num);
sum += num;
backtracking(candidates, target, i); // 不需要加一
sum -= num;
path.pop_back();
}
return;
}
vector<vector<int>> combinationSum(vector<int>& candidates, int target) {
backtracking(candidates, target, 0);
return res;
}
};
40.组合总和II
class Solution {
public:
vector<vector<int>> res;
vector<int> path;
int sum = 0;
void backtracking(vector<int> candidates, int target, int startIdx, vector<bool>& used) {
if (sum > target) return;
else if (sum == target) {
res.push_back(path);
return;
}
for (int i = startIdx; i < candidates.size(); i++) {
// used[i - 1] == true,说明同一树枝candidates[i - 1]使用过
// used[i - 1] == false,说明同一树层candidates[i - 1]使用过
if (i > 0 && candidates[i] == candidates[i - 1] && used[i - 1] == false) continue;
int num = candidates[i];
path.push_back(num);
sum += num;
used[i] = true;
backtracking(candidates, target, i + 1, used);
used[i] = false;
sum -= num;
path.pop_back();
}
return;
}
vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
// 初始化bool数组
vector<bool> used(candidates.size(), false);
sort(candidates.begin(), candidates.end());
backtracking(candidates, target, 0, used);
return res;
}
};
131.分割回文串
s.substr(起始索引,个数)
class Solution {
public:
vector<vector<string>> res;
vector<string> path;
bool isCycleTring(string& s, int start, int end) {
for (int i = start, j = end; i < j; i++, j--) {
if (s[i] != s[j]) return false;
}
return true;
}
void backtracking(string s, int startIdx) {
if (s.size() == startIdx) {
res.push_back(path);
return;
}
for (int i = startIdx; i < s.size(); i++) {
if (isCycleTring(s, startIdx, i) == true) {
string str = s.substr(startIdx, i - startIdx + 1); //s.substr(起始索引,个数);
path.push_back(str);
} else continue;
backtracking(s, i + 1);
path.pop_back();
}
return;
}
vector<vector<string>> partition(string s) {
backtracking(s, 0);
return res;
}
};
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