题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
def func():
n = int(input())
numlist = list(map(int, input().split()))
k = int(input())
print(numlist[-k]) # 机试的时候这么做
try:
while True:
func()
except EOFError:
pass
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应该说经过评估，贵公司与自己不匹配，决定不再推进后续流程