题解 | #日期累加#

#include <iostream>
using namespace std;

class Date{
private:
    size_t _year;
    size_t _month;
    size_t _date;
public:
    Date(const size_t year,const size_t month,const size_t date)
    :_year(year)
    ,_month(month)
    ,_date(date)
    {}
    int Day(size_t month)//每月天数
    {
        static int arr[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
        if((month==2)&&((_year%4==0 && _year%100!=0) || _year%400==0))
        {
            arr[2]=29;
        }
        return arr[month];
    }
    void addDate(int i)//累加
    { 
        _date+=i;
        while(_date>Day(_month))
        {
            _date-=Day(_month);
            _month++;
            if(_month>12)
            {
                _year++;
                _month=1;
            }
        }

//输出
    printf("%04d-%02d-%02d\n",_year,_month,_date);
        
    }
};


int main()
{
    int i=0;
    cin>>i;
    while(i--)
    {
        size_t y,m,d,num;
        cin>>y>>m>>d>>num;
        Date day(y,m,d);
        day.addDate(num);
    }

    return 0;
}