题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h> int main() { long long int time , hour , min ,seconds; scanf("%lld",&time); hour = time/3600; min = (time - hour*3600)/60; seconds = time%60; printf("%lld %lld %lld",hour,min,seconds); return 0; }